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void strxor(const uint8_t *in1,
const uint8_t *in2,
uint8_t *out, size_t len);
void strxor_c(const uint8_t *in,
uint8_t c,
uint8_t *out,
size_t len);
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� t | � � t |� � t |� � t t | � � � � � � |�t |� � S dS )a� From two byte strings of equal length,
create a third one which is the byte-by-byte XOR of the two.
Args:
term1 (bytes/bytearray/memoryview):
The first byte string to XOR.
term2 (bytes/bytearray/memoryview):
The second byte string to XOR.
output (bytearray/memoryview):
The location where the result will be written to.
It must have the same length as ``term1`` and ``term2``.
If ``None``, the result is returned.
:Return:
If ``output`` is ``None``, a new byte string with the result.
Otherwise ``None``.
.. note::
``term1`` and ``term2`` must have the same length.
z.Only byte strings of equal length can be xoredN�4output must be a bytearray or a writeable memoryview�9output must have the same length as the input (%d bytes))
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� t | � � |t |� � t t | � � � � � � |�t |� � S dS )a~ From a byte string, create a second one of equal length
where each byte is XOR-red with the same value.
Args:
term(bytes/bytearray/memoryview):
The byte string to XOR.
c (int):
Every byte in the string will be XOR-ed with this value.
It must be between 0 and 255 (included).
output (None or bytearray/memoryview):
The location where the result will be written to.
It must have the same length as ``term``.
If ``None``, the result is returned.
Return:
If ``output`` is ``None``, a new ``bytes`` string with the result.
Otherwise ``None``.
r � zc must be in range(256)Nr
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�t � t � | ||t t | � � � � � � dS )z!Very fast XOR - check conditions!N)r r r r )r r r s r �_strxor_directr � s0 � ����u�e�V�X�c�%�j�j�-A�-A�B�B�B�B�Br )N) �Crypto.Util._raw_apir r r r r r r r r r � r r �<module>r s� ��>D� D� D� D� D� D� D� D� D� D� D� D� D� D� D� D� (�'�)��
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