[ Avaa Bypassed ]

"""Various utility functions."""
from collections import namedtuple, OrderedDict


__unittest = True

_MAX_LENGTH = 80
def safe_repr(obj, short=False):
    try:
        result = repr(obj)
    except Exception:
        result = object.__repr__(obj)
    if not short or len(result) < _MAX_LENGTH:
        return result
    return result[:_MAX_LENGTH] + ' [truncated]...'


def strclass(cls):
    return "%s.%s" % (cls.__module__, cls.__name__)

def sorted_list_difference(expected, actual):
    """Finds elements in only one or the other of two, sorted input lists.

    Returns a two-element tuple of lists.    The first list contains those
    elements in the "expected" list but not in the "actual" list, and the
    second contains those elements in the "actual" list but not in the
    "expected" list.    Duplicate elements in either input list are ignored.
    """
    i = j = 0
    missing = []
    unexpected = []
    while True:
        try:
            e = expected[i]
            a = actual[j]
            if e < a:
                missing.append(e)
                i += 1
                while expected[i] == e:
                    i += 1
            elif e > a:
                unexpected.append(a)
                j += 1
                while actual[j] == a:
                    j += 1
            else:
                i += 1
                try:
                    while expected[i] == e:
                        i += 1
                finally:
                    j += 1
                    while actual[j] == a:
                        j += 1
        except IndexError:
            missing.extend(expected[i:])
            unexpected.extend(actual[j:])
            break
    return missing, unexpected


def unorderable_list_difference(expected, actual, ignore_duplicate=False):
    """Same behavior as sorted_list_difference but
    for lists of unorderable items (like dicts).

    As it does a linear search per item (remove) it
    has O(n*n) performance.
    """
    missing = []
    unexpected = []
    while expected:
        item = expected.pop()
        try:
            actual.remove(item)
        except ValueError:
            missing.append(item)
        if ignore_duplicate:
            for lst in expected, actual:
                try:
                    while True:
                        lst.remove(item)
                except ValueError:
                    pass
    if ignore_duplicate:
        while actual:
            item = actual.pop()
            unexpected.append(item)
            try:
                while True:
                    actual.remove(item)
            except ValueError:
                pass
        return missing, unexpected

    # anything left in actual is unexpected
    return missing, actual

_Mismatch = namedtuple('Mismatch', 'actual expected value')

def _count_diff_all_purpose(actual, expected):
    'Returns list of (cnt_act, cnt_exp, elem) triples where the counts differ'
    # elements need not be hashable
    s, t = list(actual), list(expected)
    m, n = len(s), len(t)
    NULL = object()
    result = []
    for i, elem in enumerate(s):
        if elem is NULL:
            continue
        cnt_s = cnt_t = 0
        for j in range(i, m):
            if s[j] == elem:
                cnt_s += 1
                s[j] = NULL
        for j, other_elem in enumerate(t):
            if other_elem == elem:
                cnt_t += 1
                t[j] = NULL
        if cnt_s != cnt_t:
            diff = _Mismatch(cnt_s, cnt_t, elem)
            result.append(diff)

    for i, elem in enumerate(t):
        if elem is NULL:
            continue
        cnt_t = 0
        for j in range(i, n):
            if t[j] == elem:
                cnt_t += 1
                t[j] = NULL
        diff = _Mismatch(0, cnt_t, elem)
        result.append(diff)
    return result

def _ordered_count(iterable):
    'Return dict of element counts, in the order they were first seen'
    c = OrderedDict()
    for elem in iterable:
        c[elem] = c.get(elem, 0) + 1
    return c

def _count_diff_hashable(actual, expected):
    'Returns list of (cnt_act, cnt_exp, elem) triples where the counts differ'
    # elements must be hashable
    s, t = _ordered_count(actual), _ordered_count(expected)
    result = []
    for elem, cnt_s in s.items():
        cnt_t = t.get(elem, 0)
        if cnt_s != cnt_t:
            diff = _Mismatch(cnt_s, cnt_t, elem)
            result.append(diff)
    for elem, cnt_t in t.items():
        if elem not in s:
            diff = _Mismatch(0, cnt_t, elem)
            result.append(diff)
    return result