[ Avaa Bypassed ]

drop table if exists t1, t2, t3, t4;
create table t1 (p int not null primary key, u int not null, o int not null,
unique (u), key(o)) engine=ndb;
create table t2 (p int not null primary key, u int not null, o int not null,
unique (u), key(o)) engine=ndb;
create table t3 (a int not null primary key, b int not null) engine=ndb;
create table t4 (c int not null primary key, d int not null) engine=ndb;
insert into t1 values (1,1,1),(2,2,2),(3,3,3);
insert into t2 values (1,1,1),(2,2,2),(3,3,3), (4,4,4), (5,5,5);
insert into t3 values (1,10), (2,10), (3,30), (4, 30);
insert into t4 values (1,10), (2,10), (3,30), (4, 30);
explain select * from t2 where p NOT IN (select p from t1);
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	PRIMARY	t2	ALL	NULL	NULL	NULL	NULL	#	Using where
2	DEPENDENT SUBQUERY	t1	unique_subquery	PRIMARY	PRIMARY	4	func	#	
select * from t2 where p NOT IN (select p from t1) order by p;
p	u	o
4	4	4
5	5	5
explain select * from t2 where p NOT IN (select u from t1);
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	PRIMARY	t2	ALL	NULL	NULL	NULL	NULL	#	Using where
2	DEPENDENT SUBQUERY	t1	unique_subquery	u	u	4	func	#	
select * from t2 where p NOT IN (select u from t1) order by p;
p	u	o
4	4	4
5	5	5
explain select * from t2 where p NOT IN (select o from t1);
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	PRIMARY	t2	ALL	NULL	NULL	NULL	NULL	#	Using where
2	DEPENDENT SUBQUERY	t1	index_subquery	o	o	4	func	#	
select * from t2 where p NOT IN (select o from t1) order by p;
p	u	o
4	4	4
5	5	5
explain select * from t2 where p NOT IN (select p+0 from t1);
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	PRIMARY	t2	ALL	NULL	NULL	NULL	NULL	#	Using where
2	DEPENDENT SUBQUERY	t1	ALL	NULL	NULL	NULL	NULL	#	Using where
select * from t2 where p NOT IN (select p+0 from t1) order by p;
p	u	o
4	4	4
5	5	5
drop table t1;
drop table t2;
create table t1 (p int not null primary key, u int not null) engine=ndb;
insert into t1 values (1,1),(2,2),(3,3);
create table t2 as 
select t1.*
from t1 as t1, t1 as t2, t1 as t3, t1 as t4, t1 as t5, t1 as t6, t1 as t7, t1 as t8
where t1.u = t2.u
and t2.u = t3.u
and t3.u = t4.u
and t4.u = t5.u
and t5.u = t6.u
and t6.u = t7.u
and t7.u = t8.u;
select * from t2 order by 1;
p	u
1	1
2	2
3	3
select * from t3 where a = any (select c from t4 where c = 1) order by a;
a	b
1	10
select * from t3 where a in (select c from t4 where c = 1) order by a;
a	b
1	10
select * from t3 where a <> some (select c from t4 where c = 1) order by a;
a	b
2	10
3	30
4	30
select * from t3 where a > all (select c from t4 where c = 1) order by a;
a	b
2	10
3	30
4	30
select * from t3 where row(1,10) = (select c,d from t4 where c = 1) order by a;
a	b
1	10
2	10
3	30
4	30
select * from t3 where exists (select * from t4 where c = 1) order by a;
a	b
1	10
2	10
3	30
4	30
drop table if exists t1, t2, t3, t4;
create table t (k int, uq int, unique key ix1 (uq)) engine = ndb;
insert into t values (1,3), (3,6), (6,9), (9,1);
select * from t where 
k in (select uq from t as subq where subq.k>10);
k	uq
drop table if exists t;
End of 5.1 tests